Satisfactory Production Ratios: Smelters per Miner
A Normal Mk.1 Miner feeds 2 Iron or Copper Smelters: 60 ore/min ÷ 30 per Smelter. At 100% clock, Mk.2 and Mk.3 feed 4 and 8 Smelters on Normal nodes. [1]
| Normal node | Ore/min | Smelters |
|---|---|---|
| Miner Mk.1 | 60 | 2 |
| Miner Mk.2 | 120 | 4 |
| Miner Mk.3 | 240 | 8 |
Iron/Copper, standard ingots; no leftover ore. All rates below use 100% clock, no Somersloops and continuous supply. [1]
Two-Smelter setup: split the 60 ore/min input evenly into 2 branches of 30 ore/min. Mk.1 belts carry the input and each output; each Smelter makes 30 ingots/min, or 60 ingots/min merged. Keep both outputs moving. [1] [4]
Reinforced Iron Plates: one standard Assembler makes 5/min; a balanced 10/min needs 120 Iron Ore/min and 14 production buildings (excluding miners and logistics). [1]
How many Reinforced Iron Plates?
One standard Assembler makes 5 Reinforced Iron Plates/min. The smallest balanced whole-building chain makes 10/min from 120 Iron Ore/min: 4 Smelters + 3 Plate Constructors + 2 Rod Constructors + 3 Screw Constructors + 2 Assemblers. These 14 production buildings run continuously at 100% clock, with standard recipes, no Somersloops and no intermediate surplus; miners and logistics are excluded. [1]
Reinforced Iron Plate calculator → · Compare the whole-chain row ↓
Reinforced Iron Plate calculation: all six balancing steps
Step 1 — Choose the whole set: the one-Assembler solution contains fractional Constructors; multiplying it by 2 gives 2 Assemblers × 5 = 10 plates/min.
Step 2 — Supply assembly: 2 × (30 Iron Plate/min + 60 Screws/min) = 60 Iron Plate/min + 120 Screws/min.
Step 3 — Make Iron Plates: 60 ÷ 20 = 3 Constructors, consuming 90 Iron Ingots/min.
Step 4 — Make Screws and Rods: 120 ÷ 40 = 3 Screw Constructors; their 30 Rods/min need 2 Rod Constructors.
Step 5 — Smelt the combined demand: 90 + 30 = 120 Ingots/min; ÷ 30 = 4 Smelters consuming 120 Iron Ore/min.
Step 6 — Check the minimum: stage counts 4 : 3 : 2 : 3 : 2 share no integer divisor greater than one. Every intermediate output equals downstream consumption. [1]
How many smelters or first-stage machines per miner?
Exact machine equivalents are supply ÷ recipe input. Fractions need clock tuning or intermittent operation; “full” counts only continuously fed machines. Other ingredients are supplied separately. [1]
Purity multipliers: Impure ×0.5; Normal ×1; Pure ×2. These are throughput scenarios, not a claim that every purity exists for every resource on the map. [2]
Iron and Copper Smelters
Iron Ore → Iron Ingot: each Smelter needs 30 Iron Ore/min. Output per machine: 30 Iron Ingot/min. [1]
Copper Ore → Copper Ingot: each Smelter needs 30 Copper Ore/min. Output per machine: 30 Copper Ingot/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 30 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 1 machine | 1 + 0 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 2 machines | 2 + 0 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 4 machines | 4 + 0 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 8 machines | 8 + 0 ore/min |
| Mk.3 / Pure | 480 | 16 machines | 16 + 0 ore/min |
Caterium Smelters, Steel Foundries and Concrete Constructors
Caterium Ore → Caterium Ingot: each Smelter needs 45 Caterium Ore/min. Output per machine: 15 Caterium Ingot/min. [1]
Iron Ore + Coal → Steel Ingot: each Foundry needs 45 Iron Ore/min + 45 Coal/min. Supply equal amounts of both: the table’s ore rate and leftover apply to each input separately, not their sum. Output per machine: 45 Steel Ingot/min. [1]
Limestone → Concrete: each Constructor needs 45 Limestone/min. Output per machine: 15 Concrete/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 45 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 2/3 machines | 0 + 30 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 4/3 machines | 1 + 15 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 8/3 machines | 2 + 30 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 16/3 machines | 5 + 15 ore/min |
| Mk.3 / Pure | 480 | 32/3 machines | 10 + 30 ore/min |
Smallest whole-building production ratios
Each row is the smallest balanced set for that standard chain: all production buildings run continuously at full clock, with no intermediate surplus. Scale the entire row by a whole number to keep that balance. Counts exclude miners and logistics; each stage is named so parallel branches stay visible. [1]
| Part / output per min | Buildings per stage | Raw inputs per min |
|---|---|---|
| Iron Plate20/min · 2 buildings |
| 30 Iron Ore |
| Iron Rod30/min · 3 buildings |
| 30 Iron Ore |
| Screws120/min · 6 buildings |
| 30 Iron Ore |
| Reinforced Iron Plate10/min · 14 buildings |
| 120 Iron Ore |
| Rotor8/min · 16 buildings |
| 90 Iron Ore |
| Modular Frame20/min · 64 buildings |
| 480 Iron Ore |
| Wire60/min · 3 buildings |
| 30 Copper Ore |
| Cable30/min · 4 buildings |
| 30 Copper Ore |
| Concrete15/min · 1 building |
| 45 Limestone |
| Steel Beam45/min · 7 buildings |
| 180 Iron Ore180 Coal |
| Steel Pipe60/min · 5 buildings |
| 90 Iron Ore90 Coal |
“Smallest” requires every intermediate to balance with no surplus; a smaller factory can produce less using idle time or clock tuning. These are default-recipe sets, not alternate-recipe comparisons. Use the optimizer for other recipes or Modular Frame calculator for a custom target.
Advanced miner recipes: Quartz, Sulfur, Uranium, Bauxite and SAM
Open a named recipe group for its inputs, outputs and all nine miner/purity scenarios. Matching input rates share one matrix; they do not share ingredients or outputs. Purities are throughput scenarios, not map-node availability. [1]
Raw Quartz → Quartz Crystal: miner ratios
Raw Quartz → Quartz Crystal: each Constructor needs 37.5 Raw Quartz/min. Output per machine: 22.5 Quartz Crystal/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 37.5 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 4/5 machines | 0 + 30 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 8/5 machines | 1 + 22.5 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 16/5 machines | 3 + 7.5 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 32/5 machines | 6 + 15 ore/min |
| Mk.3 / Pure | 480 | 64/5 machines | 12 + 30 ore/min |
Raw Quartz → Silica: miner ratios
Raw Quartz → Silica: each Constructor needs 22.5 Raw Quartz/min. Output per machine: 37.5 Silica/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 22.5 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 4/3 machines | 1 + 7.5 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 8/3 machines | 2 + 15 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 16/3 machines | 5 + 7.5 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 32/3 machines | 10 + 15 ore/min |
| Mk.3 / Pure | 480 | 64/3 machines | 21 + 7.5 ore/min |
Sulfuric Acid and Encased Uranium Cells: inputs, outputs and miner ratios
Sulfur → Sulfuric Acid: each Refinery needs 50 Sulfur/min; also supply 50 m³ Water/min. Output per machine: 50 m³ Sulfuric Acid/min. [1]
Uranium → Encased Uranium Cell: each Blender needs 50 Uranium/min; also supply 15 Concrete/min; 40 m³ Sulfuric Acid/min. Output per machine: 25 Encased Uranium Cell/min; 10 m³ Sulfuric Acid/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 50 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 3/5 machines | 0 + 30 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 6/5 machines | 1 + 10 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 12/5 machines | 2 + 20 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 24/5 machines | 4 + 40 ore/min |
| Mk.3 / Pure | 480 | 48/5 machines | 9 + 30 ore/min |
Alumina Solution and Reanimated SAM: inputs, outputs and miner ratios
Bauxite → Alumina Solution: each Refinery needs 120 Bauxite/min; also supply 180 m³ Water/min. Output per machine: 120 m³ Alumina Solution/min; 50 Silica/min. [1]
SAM → Reanimated SAM: each Constructor needs 120 SAM/min. Output per machine: 30 Reanimated SAM/min. [1]
Standard recipes, 100% clock; keep every output flowing. Exact = supply ÷ 120 ore/min. Rows group equal supplies; apply separately to each route, with sufficient belts.
| Miner / purity | Ore/min | Exact machines | Full machines + ore/min left |
|---|---|---|---|
| Mk.1 / Impure | 30 | 1/4 machines | 0 + 30 ore/min |
| Mk.1 / Normal; Mk.2 / Impure | 60 | 1/2 machines | 0 + 60 ore/min |
| Mk.1 / Pure; Mk.2 / Normal; Mk.3 / Impure | 120 | 1 machine | 1 + 0 ore/min |
| Mk.2 / Pure; Mk.3 / Normal | 240 | 2 machines | 2 + 0 ore/min |
| Mk.3 / Pure | 480 | 4 machines | 4 + 0 ore/min |
Belt and pipe limits: how many machines fill a belt?
Conveyor capacities come directly from the export. The example is standard Screws: 40 items/min per final Constructor; a complete minimum chain makes 120/min. “Final” counts only Screw Constructors; the expandable chain includes smelting and rods. [1]
| Belt | Items/min | Final Constructors | Whole sets / spare |
|---|---|---|---|
| Mk.1 | 60 | 3/2 | 0 / 60 |
| Mk.2 | 120 | 3 | 1 / 0 |
| Mk.3 | 270 | 27/4 | 2 / 30 |
| Mk.4 | 480 | 12 | 4 / 0 |
| Mk.5 | 780 | 39/2 | 6 / 60 |
| Mk.6 | 1,200 | 30 | 10 / 0 |
Whole sets = complete 120/min Screw chains that fit without exceeding the belt. Spare = unused belt capacity, items/min. Exact-fill columns are capacity equivalents; fractions need clock tuning or intermittent operation.
Every stage needed to fill each Screw belt exactly
| Belt | Machine equivalents by recipe | Whole buildings? |
|---|---|---|
| Mk.1 | 3/2 Constructor — Screws1 Constructor — Iron Rod1/2 Smelter — Iron Ingot | Fractional |
| Mk.2 | 3 Constructor — Screws2 Constructor — Iron Rod1 Smelter — Iron Ingot | Yes |
| Mk.3 | 27/4 Constructor — Screws9/2 Constructor — Iron Rod9/4 Smelter — Iron Ingot | Fractional |
| Mk.4 | 12 Constructor — Screws8 Constructor — Iron Rod4 Smelter — Iron Ingot | Yes |
| Mk.5 | 39/2 Constructor — Screws13 Constructor — Iron Rod13/2 Smelter — Iron Ingot | Fractional |
| Mk.6 | 30 Constructor — Screws20 Constructor — Iron Rod10 Smelter — Iron Ingot | Yes |
Check the miner belt too: Normal Mk.1 needs at least Mk.1 for 60 ore/min; Normal Mk.2 needs at least Mk.2 for 120 ore/min; Normal Mk.3 needs at least Mk.3 for 240 ore/min. A downstream splitter cannot increase the capacity of the belt leaving the miner. [1] [4]
| Pipeline | Capacity (m³/min) | Source |
|---|---|---|
| Mk.1 | 300 | [3] Wiki |
| Mk.2 | 600 | [3] Wiki |
Pipeline capacities are wiki-sourced constants alongside this versioned calculation; the export contains no pipe-capacity field. They are upper transfer limits; liquid head lift and fluid flow still matter. [3]
Splitter patterns that follow from the demand
A basic splitter distributes items in sequence among available outputs. Like the two-Smelter setup above, this three-way split assumes unobstructed outputs and sufficient belts; input exactly matches total demand. [4]
- One input → 3 Smelters: 90 Iron Ore/min ÷ 3 = 30 per branch. Use at least a Mk.2 input belt. [1]
The 3-way pattern needs 90 ore/min delivered to that splitter; it is a supplied-rate example, not a separate miner-purity row. An inline manifold can meet the same steady demand after upstream buffers fill, provided downstream paths remain open and total supply is sufficient. The ratio fixes demand; it does not specify startup time. [4]
Sources
- Download versioned production ratios (JSON) — game data v1.2.3.1, exported 2026-06-25, computed 2026-10-29. Generated from
src/data/sat.json, whose provenance identifies SCIM’s game-Docs-derived export; includes the source hash and calculation method. - Official Wiki: Miner — mining speed — purity factors and extraction formula.
- Official Wiki: Pipelines — capacities, liquid head lift and flow behavior; verified 2026-10-29.
- Official Wiki: Conveyor Splitter — usage — output distribution, backpressure and belt connections.
Production ratios FAQ
How many smelters per miner in Satisfactory?
On a Normal Iron or Copper node at 100% clock, Miner Mk.1/Mk.2/Mk.3 feed 2/4/8 Smelters. Each Smelter uses 30 ore/min. Impure nodes halve those counts; Pure nodes double them. Caterium uses a different ore rate. [1] [2]
What is the best smelter setup in Satisfactory?
Match the ore supply and outgoing belts to the recipe. A Normal Mk.1 Iron Miner supplies 60 ore/min: split it between 2 Smelters at 30 ore/min each. Keep ingot output moving; use the miner table for other tiers and purities. [1] [4]
How many Reinforced Iron Plates can I make?
One standard Assembler makes 5/min. The smallest balanced whole-building chain makes 10/min from 120 Iron Ore/min: 4 Smelters, 3 Plate Constructors, 2 Rod Constructors, 3 Screw Constructors and 2 Assemblers. [1]
How many smelters does a Caterium miner need?
A Normal Mk.1 Miner supplies 60 Caterium Ore/min. At 45 ore/min per Smelter, that is 4/3 Smelter equivalents: 1 fully fed Smelter plus 15 ore/min left over. Another full-clock Smelter would run intermittently. [1]
How many Screw Constructors fill a conveyor belt?
Each standard Screw Constructor produces 40 Screws/min. Belt Mk.1–Mk.6 therefore need 3/2, 3, 27/4, 12, 39/2, 30 Constructor equivalents respectively. Fractional counts require clock tuning or intermittent operation; the belt table also shows complete whole-building chains. [1]
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